JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\alpha

and

\beta

are roots of the equation

x^{2}+p x+\frac{3 p}{4}=0

, such that

|\alpha-\beta|=\sqrt{10}

, then

p

belongs to the set :

View answer and explanation

Correct option: C

\{-2,5\}

Option C (

\{-2,5\}

) is correct because solving for p using the given condition

|\alpha-\beta|=\sqrt{10}

yields the set

\{-2,5\}

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