If $y = \frac{{\sec x - \tan x}}{{\sec x + \tan x}},$ then $\frac{{dy}}{{dx}}$ equals

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y = \frac{{\sec x - \tan x}}{{\sec x + \tan x}},

then

\frac{{dy}}{{dx}}

equals

View answer and explanation

Correct option: B

- 2\sec x{(\sec x - \tan x)^2}

Option B (

- 2\sec x{(\sec x - \tan x)^2}

) is correct because it is the derivative of the given function y with respect to x, obtained after simplification and applying the chain rule.

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