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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
If two equations x2+a2=1−2ax{x^2} + {a^2} = 1 - 2ax and x2+b2=1−2bx{x^2} + {b^2} = 1 - 2bx have only one common root, then
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Correct option: C
a−b=2a - b = 2
Option C (a - b = 2) is correct because by applying the condition for common roots and simplifying the resulting equation, we arrive at a - b = 2.

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