If $y = {5^x}{x^5},$, then $\frac{{dy}}{{dx}}$ is

${5^x}\left( {{x^5}\log 5 - 5{x^4}} \right)$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y = {5^x}{x^5},

, then

\frac{{dy}}{{dx}}

View answer and explanation

Correct option: D

{5^x}({x^5}\log 5 + 5{x^4})

Option D (

{5^x}({x^5}\log 5 + 5{x^4}))

is correct because it is the result of applying the product rule and differentiating each term correctly.

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