JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

u = \log \left( {\frac{{{x^2} + {y^2}}}{{x + y}}} \right),

then the value of

x\frac{{\partial u}}{{\partial x}} + y\frac{{\partial u}}{{\partial y}}

View answer and explanation

Correct option: C

Option C (1) is correct because the expression

x\frac{{\partial u}}{{\partial x}} + y\frac{{\partial u}}{{\partial y}}

simplifies to 1 using Euler's theorem for homogeneous functions.

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