JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

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Application +4 | -1

The roots of the equation

{(a + \sqrt b )^{{x^2} - 15}} + {(a - \sqrt b )^{{x^2} - 15}} = 2a,

where

a^2-b=1

, are

View answer and explanation

Correct option: B

\pm 4, \pm \sqrt{14}

Option B (

\pm 4, \pm \sqrt{14}

) is correct because these values satisfy the given equation after simplification and solving for x.

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\alpha ,\beta

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\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)