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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy
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Application +4 | -1
If the roots of the equation (b−c)x2+(c−a)x+(a−b)=0(b-c) x^2+(c-a) x+(a-b)=0 be equal and a+c=kba+c=k b. Then the value of k=\boldsymbol{k}=
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Correct option: A
2
Option A (2) is correct because, with equal roots and a+c=kb, solving the quadratic equation leads to k=2.

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