The angular momentum of electron in ${n^{{\rm{th}}}}$ orbit is given by

JEE PHYSICS MCQ: ATOMS

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The angular momentum of electron in

{n^{\mathrm{th}}}

orbit is given by

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Correct option: C

n\frac{h}{{2\pi }}

Option C (

n\frac{h}{{2\pi }}

) is correct because, according to Bohr's quantization condition, the angular momentum of an electron in the nth orbit is an integer multiple of

h/2\pi

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n

=2

{n}=1

\lambda_0

\lambda_0

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m