Silver (atomic weight $ = 108\;{\rm{g}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$) has a density of $10.5\;g\;{\rm{c}}{{\rm{m}}^{ - 3}}.$ The number of silver atoms on a surface of area ${10^{ - 12}}\;{{\rm{m}}^2}$ can be expressed in scientific notation as $y \times {10^x}.$ The value of $x$ is

JEE CHEMISTRY MCQ: SOLID STATE

1 Hard

1 of 1

Application +4 | -1

Silver (atomic weight

= 108\;\mathrm{g}\;\mathrm{mo}{\mathrm{l}^{ - 1}}

) has a density of

10.5\;g\;\mathrm{c}{\mathrm{m}^{ - 3}}.

The number of silver atoms on a surface of area

{10^{ - 12}}\;{\mathrm{m}^2}

can be expressed in scientific notation as

y \times {10^x}.

The value of

x

View answer and explanation

Correct option: C

Option C is correct because the calculation involves finding the volume of a silver atom, then its area, and finally dividing the given surface area by the area of each silver atom.

JEE CHEMISTRY MCQ: SOLID STATE

More Questions from SOLID STATE