Question

Consider a body centred cubic (BCC) arrangement, let $\mathrm{d}_{\mathrm{e}}$, $\mathrm{d}_{\mathrm{fd}}, \mathrm{d}_{\mathrm{bd}}$ be the distances between successive atoms located along the edge, the face-diagonal, the body diagonal respectively in a unit cell. Their order is given by -

Accepted Answer

$\mathrm{d}_{\mathrm{fd}}>\mathrm{d}_{\mathrm{e}}>\mathrm{d}_{\mathrm{fd}}$

Answer

$\mathrm{d}_{\mathrm{e}}<\mathrm{d}_{\mathrm{fd}}<\mathrm{d}_{\mathrm{bd}}$

Answer

$\mathrm{d}_{\mathrm{fd}}>\mathrm{d}_{\mathrm{bd}}>\mathrm{d}_{\mathrm{e}}$

Answer

$\mathrm{d}_{\mathrm{bd}}>\mathrm{d}_{\mathrm{e}}>\mathrm{d}_{\mathrm{fd}}$

JEE CHEMISTRY MCQ: SOLID STATE

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