JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

f(x+y)=f(x) \cdot f(y) \forall x \cdot y

and

f(5)=2

f^{\prime}(0)=3

, then

f^{\prime}(5)

View answer and explanation

Correct option: C

Option C (6) is correct because

f'(5)

is calculated to be 6 using the given functional equation and derivative at 0.

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