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JEE PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium
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Application +4 | -1
A force F→=(i^+2j^+3k^)N\overrightarrow F = (\hat i + 2\hat j + 3\hat k)N displaces a particle from position r1→=(i^+j^+k^)m\overrightarrow {{r_1}} = (\hat i + \hat j + \hat k)m to position r2→=(j^+k^)m\overrightarrow {{r_2}} = (\hat j + \hat k)m. The work done by the force in doing so is
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Correct option: A
– 1 J
Option A (– 1 J) is correct because the work done is the dot product of the force and the displacement vector.

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