JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Hard

1 of 1

Application +4 | -1

A uniformly wound solenoid coil of self-inductance

1.8 \times \,\,{10^{ - 4}}\,\mathrm{H}

and resistance

\mathrm{6}\,\,\mathrm{\Omega }

is broken up into two identical coils. These identical coils are then connected in parallel across a

\mathrm{12}\,\,\mathrm{V}

battery of negligible resistance. The time constant for the current in the circuit is

View answer and explanation

Correct option: C

0.3\,\, \times {10^{ - 4}}\,\mathrm{s}

Option C (

0.3\, \times {10^{ - 4}}\,\mathrm{s}

) is correct because it is the time constant calculated after breaking the coil and connecting them in parallel.

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