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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
The solution of tan⁡−12θ+tan⁡−13θ=π4{\tan ^{ - 1}}2\mathrm{\theta } + {\tan ^{ - 1}}3\mathrm{\theta } = \frac{\pi }{4} is
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Correct option: C
16\frac{1}{6}
Option C (16\frac{1}{6}) is correct because solving the equation tan⁡−12θ+tan⁡−13θ=π4{\tan ^{ - 1}}2\theta + {\tan ^{ - 1}}3\theta = \frac{\pi }{4} using the tangent addition formula yields θ=16\theta = \frac{1}{6} as the valid solution.

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