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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

If

{\cos ^{ - 1}}p + {\cos ^{ - 1}}q + {\cos ^{ - 1}}r = 3\pi

, then

{p^2} + {q^2} + {r^2} + 2pqr

is equal to

View answer and explanation

Correct option: B

1

Option B (1) is correct because the given condition

{\cos ^{ - 1}}p + {\cos ^{ - 1}}q + {\cos ^{ - 1}}r = 3\pi

implies

p = q = r = -1

, and thus

{p^2} + {q^2} + {r^2} + 2pqr = 1

.

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