JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

Let

f(\theta)=\sin \left(\tan ^{-1}\left(\frac{\sin \theta}{\sqrt{\cos 2 \theta}}\right)\right)

, where

-\frac{\pi}{4}<\theta<\frac{\pi}{4}

. Then, the value of

\frac{d}{d(\tan \theta)} \cdot f(\theta)

, is

View answer and explanation

Correct option: A

Option A (1) is correct because after simplification,

f(\theta) = \tan \theta

, and the derivative of

\tan \theta

with respect to

\tan \theta

is 1.

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