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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1
A light-emitting diode ( LEDL E D ) has the voltage drop of 2 V2 \mathrm{~V} across it and passes the current of 10 A10 \mathrm{~A}, when it operates with the 6 V6 \mathrm{~V} battery with a limiting resistor ' RR '. What is the value of R\mathrm{R} ?
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Correct option: D
400 kΩ400 \mathrm{~k} \Omega
Option D (400 kΩ400 \mathrm{~k} \Omega) is correct because it is calculated using Ohm's law, considering the voltage drop across the resistor.

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