JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\cos ^{-1}\left[\sin \left(\sin ^{-1}(\sin x)\right)\right]=0

, then the value of

\tan \frac{x}{2}

(x \in[0,2 \pi])

View answer and explanation

Correct option: A

Option A (1) is correct because the equation simplifies to sin x = 1, which implies x = π/2, and thus tan(x/2) = tan(π/4) = 1.

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{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)