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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
f(x)f\left( x \right) is a polynomial of degree 2, f(0)=4,f′(0)=3f\left( 0 \right) = 4,f'\left( 0 \right) = 3 and f′′(0)=4f''\left( 0 \right) = 4, then f(−1)f\left( { - 1} \right) is equal to
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Correct option: A
3
Option A (3) is correct because given the conditions, the polynomial is determined to be f(x)=2x2+3x+4f(x) = 2x^2 + 3x + 4, and f(−1)=3f(-1) = 3.

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