If $x=f(t), y=g(t)$, then $\frac{d^2 y}{d x^2}=\ldots \ldots$

$\frac{f^{\prime} g^{\prime \prime}-g^{\prime} f^{\prime}}{(f)^2}$

$\frac{f^{\prime \prime}}{g^{\prime \prime}}$

$\frac{{g''}}{{{f^{\prime \prime }}}}$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

x=f(t), y=g(t)

, then

\frac{d^2 y}{d x^2}=\ldots \ldots

View answer and explanation

Correct option: B

\frac{{{f^\prime }g'' - {g^\prime }{f^{\prime \prime }}}}{{{{(f)}^3}}}

Option B is correct because it represents the correct formula for the second derivative of y with respect to x when both x and y are functions of t.

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