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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Suppose a pure Si{Si} crystal has 5×10285 \times 10^{28} atoms m−3{m}^{-3}. It is doped with 1ppm1 {ppm} concentration of pentavalent Arsenic. Calculate the number of holes formed. (ni=2.5×1016 m−3)\left(n_i=2.5 \times 10^{16} {~m}^{-3}\right).
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Correct option: B
1.25×1010 m−31.25 \times 10^{10} {~m}^{-3}
Option B (1.25×1010 m−31.25 \times 10^{10} {~m}^{-3}) is correct because it is the number of holes calculated using the mass action law in semiconductors.

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