JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

x \in\left(\frac{3 \pi}{2}, 2 \pi\right)

then value of the expression

\sin ^{-1}\left(\cos \left(\cos ^{-1}(\cos x)+\sin ^{-1}(\sin x)\right)\right)

equals

View answer and explanation

Correct option: B

\frac{\pi}{2}

Option B (

\frac{\pi}{2}

) is correct because the expression simplifies to

\sin^{-1}(1)

, which equals

\frac{\pi}{2}

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{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)