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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
A solution of the equation tan⁡−1(1+x)+tan⁡−1(1−x)=π2,{\tan ^{ - 1}}\left( {1 + x} \right) + {\tan ^{ - 1}}\left( {1 - x} \right) = \frac{\pi }{2}, is
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Correct option: C
x=0x = 0
Option C is correct because solving the equation tan⁡−1(1+x)+tan⁡−1(1−x)=π2{\tan ^{ - 1}}\left( {1 + x} \right) + {\tan ^{ - 1}}\left( {1 - x} \right) = \frac{\pi }{2} using trigonometric identities leads to x=0x = 0.

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