How many unit cells are present in a cube shaped ideal crystal of ${\rm{NaCl}}$ of mass 1.00g? $\left[ {{\rm{Atomic}}\;{\rm{ masses}}:{\rm{Na}} = 23,\;{\rm{Cl}} = 35.5} \right]$

JEE CHEMISTRY MCQ: SOLID STATE

1 Hard

1 of 1

Application +4 | -1

How many unit cells are present in a cube shaped ideal crystal of

\mathrm{NaCl}

of mass 1.00g?

\left[ {\mathrm{Atomic}\;\mathrm{ masses}:\mathrm{Na} = 23,\;\mathrm{Cl} = 35.5} \right]

View answer and explanation

Correct option: A

2.57 \times {10^{21}}

Option A (

2.57 \times {10^{21}}

) is correct because it is calculated by dividing the total mass by the mass of one unit cell.

Practice All Chapter MCQs →

{CaF}_2

{F}^{-}

\mathrm{d}_{\mathrm{e}}

\mathrm{d}_{\mathrm{fd}}, \mathrm{d}_{\mathrm{bd}}

\mathrm{AB}_2

\mathrm{A}