JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y = \sin \left( {m{{\sin }^{ - 1}}x} \right)

, then

\left( {1 - {x^2}} \right)\frac{{{d^2}y}}{{d{x^2}}} =

View answer and explanation

Correct option: B

x \frac{d y}{d x}-m^2 y

Option B (

x \frac{d y}{d x}-m^2 y

) is correct because it is the result of differentiating the given equation twice and rearranging the terms.

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