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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
d2xdy2\frac{d^{2} x}{d y^{2}} equals :
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Correct option: C
−(d2ydx2)(dydx)−3-\left(\frac{d^{2} y}{d x^{2}}\right)\left(\frac{d y}{d x}\right)^{-3}
Option C (-(d2ydx2\frac{{d^{2}y}}{{dx^{2}}})(dydx\frac{{dy}}{{dx}})−3^{-3}) is correct because it represents the correct expression for d2xdy2\frac{{d^{2}x}}{{dy^{2}}} in terms of derivatives of y with respect to x.

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