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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1
In an inductor, the current I\mathrm{I} varies with time t as I=4+4t\mathrm{I=4+4 t}. If the emf induced in the inductor is 8 mV8 \mathrm{~mV}, what is self inductance? (Here current is in ampere and time is in second)
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Correct option: D
2×10−3 H2 \times 10^{-3} \mathrm{~H}
Option D (2×10−3 H2 \times 10^{-3} \mathrm{~H}) is correct because it is the self-inductance calculated using the formula ∣e∣=LdIdt|e| = L \frac{dI}{dt}.

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