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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
If f(x)=∣x−2∣+∣x+1∣−x,f\left( x \right) = \left| {x - 2} \right| + \left| {x + 1} \right| - x, then f′(−10)f'\left( { - 10} \right) is equal to
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Correct option: A
−3- 3
Option A (-3) is correct because for x < -1, the function simplifies to f(x) = -3x + 1, and thus f'(x) = -3.

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