If $y=\log _{x^2+4}\left(7 x^2-5 x+1\right)$, then $\frac{d y}{d x}=$

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y=\log _{x^2+4}\left(7 x^2-5 x+1\right)

, then

\frac{d y}{d x}=

View answer and explanation

Correct option: A

\frac{1}{\log _e\left(x^2+4\right)}\left(\frac{14 x-5}{7 x^2-5 x+1}-\frac{2 x y}{x^2+4}\right)

Option A is correct because it is the result of applying the change of base formula and the quotient rule for differentiation.

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