JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y=\log _a x+\log _x a+\log _x x+\log _a a

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: D

\frac{1}{x \log a}-\frac{\log a}{x(\log x)^2}

Option D (

\frac{1}{x \log a}-\frac{\log a}{x(\log x)^2}

) is correct because after applying the change of base formula for logarithms and differentiating, the derivative is found to be

\frac{1}{x \log a}-\frac{\log a}{x(\log x)^2}

More Questions from DIFFERENTIATION

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