If $ - 1 \le x \le 0$, then ${\cos ^{ - 1}}\left( {2{x^2} - 1} \right)$ equals

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

- 1 \le x \le 0

, then

{\cos ^{ - 1}}\left( {2{x^2} - 1} \right)

equals

View answer and explanation

Correct option: C

2\;\pi - 2{\cos ^{ - 1}}x

The correct answer is C (

2\;\pi - 2{\cos ^{ - 1}}x

) because considering the given range of x,

{\cos ^{ - 1}}(2x^2 - 1)

simplifies to

2\pi - 2{\cos ^{ - 1}}x

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