Mosley measured the frequency $\left( f \right)$ of the characteristic $X$-rays from many metals of different atomic number $\left( {\rm{Z}} \right)$ and represented his results by a relation known as Mosley’s law. This law is (a, b are constants)

$Z = a{\left( {f - b} \right)^2}$

${f^2} = a\left( {Z - b} \right)$

$f = a{\left( {Z - b} \right)^{1/2}}$

JEE PHYSICS MCQ: ATOMS

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Mosley measured the frequency

\left( f \right)

of the characteristic

X

-rays from many metals of different atomic number

\left( \mathrm{Z} \right)

and represented his results by a relation known as Mosley’s law. This law is (a, b are constants)

View answer and explanation

Correct option: A

f = a{\left( {Z - b} \right)^2}

Option A (

f = a{\left( {Z - b} \right)^2}

) is correct because Mosley's law relates the frequency of characteristic X-rays to the atomic number of the metal.