JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

\frac{d^2 x}{d y^2}

equals

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Correct option: D

-\left(\frac{d^2 y}{d x^2}\right)\left(\frac{d y}{d x}\right)^{-3}

Option D (- (d²y/dx²) * (dy/dx)^-3) is correct because it is derived from the chain rule and inverse function differentiation.

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