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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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The Boolean equation x=[(A+B‾)⋅(B+C)]⋅B\mathrm{x}=[(\mathrm{A}+\overline{\mathrm{B}}) \cdot(\mathrm{B}+\mathrm{C})] \cdot \mathrm{B} can be simplified to
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Correct option: C
x=A⋅B\mathrm{x}=\mathrm{A} \cdot \mathrm{B}
Option C (x=A⋅B) is correct because the Boolean expression simplifies to A AND B using Boolean algebra rules.

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