JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

\alpha

and

\beta

are the roots of the equation

a{x^2} + bx + c = 0

and, if

p{x^2} + qx + r = 0

has roots

\frac{{1 - \alpha }}{\alpha }

and

\frac{{1 - \beta }}{\beta }

, then

r

is equal to

View answer and explanation

Correct option: B

a + b + c

Option B (

a + b + c

) is correct because substituting the roots into the transformed quadratic equation leads to r = a + b + c.

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

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9{x^2} - 18\left| x \right| + 5 = 0

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