If $y = {\sec ^{ - 1}}\frac{{x + 1}}{{x - 1}} + {\sin ^{ - 1}}\frac{{x - 1}}{{x + 1}}$, then $\frac{{dy}}{{dx}}$ is

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

y = {\sec ^{ - 1}}\frac{{x + 1}}{{x - 1}} + {\sin ^{ - 1}}\frac{{x - 1}}{{x + 1}}

, then

\frac{{dy}}{{dx}}

View answer and explanation

Correct option: B

Option B (0) is correct because the expression simplifies to a constant, and the derivative of a constant is zero.

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