JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

\frac{{{d^2}x}}{{d{y^2}}}{\left( {\frac{{dy}}{{dx}}} \right)^3} + \frac{{{d^2}y}}{{d{x^2}}} = k

, then

k

is equal to

View answer and explanation

Correct option: A

Option A (0) is correct because the given expression simplifies to zero using the relationship between first and second derivatives.

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