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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Let f(x+y)=f(x)f(y)f\left( {x + y} \right) = f\left( x \right)f\left( y \right) and f(x)=1+(sin⁡2x)g(x)f\left( x \right) = 1 + \left( {\sin 2x} \right)g\left( x \right) where g(x)g\left( x \right) is continuous. Then, f′(x)f'\left( x \right) equals
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Correct option: B
2f(x)g(0)2f\left( x \right)g\left( 0 \right)
Option B (2f(x)g(0)2f\left( x \right)g\left( 0 \right)) is correct because it is the result of applying the limit definition of the derivative and using the given functional equation.

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