JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

g

be the inverse function of differentiable function

f

and

f'(x) = \frac{{{x^{10}}}}{{1 + {x^2}}}.

g(2) = a,\,\,

then

g'(2)

is equal to

View answer and explanation

Correct option: B

\frac{{1 + {a^2}}}{{{a^{10}}}}

Option B (

\frac{{1 + {a^2}}}{{{a^{10}}}}

\) is correct because it is the value of the derivative of the inverse function g at 2, calculated using the derivative of the original function f.

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