JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\sum\limits_{r=1}^x \tan ^{-1}\left(\frac{1}{1+r+r^2}\right)

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: B

\frac{1}{1+(1+x)^2}

Option B (

\frac{1}{1+(1+x)^2}

) is correct because the summation simplifies to a telescoping series, and the derivative is then straightforward.

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