If $y = \frac{{1 + {x^2} + {x^4}}}{{1 + x + {x^2}}}{\rm{ \,\,and \,\,}}\frac{{dy}}{{dx}} = ax + b,$ then

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Application +4 | -1

y = \frac{{1 + {x^2} + {x^4}}}{{1 + x + {x^2}}}\mathrm{ \,\,and \,\,}\frac{{dy}}{{dx}} = ax + b,

then

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Correct option: C

a = 2,\,\,b = - 1

Option C (

a = 2,\,\,b = - 1

) is correct because after simplifying the given expression and differentiating, the coefficients of x and the constant term match these values.

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