JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

f\left( {x,y} \right) = \frac{{\cos (x - 4y)}}{{\cos \left( {x + 4y} \right)}},

then

{\left. {\frac{{\partial f}}{{\partial x}}} \right|_{y = \frac{\pi }{2}}}

is equal to

View answer and explanation

Correct option: B

Option B (0) is correct because when y = π/2, the function simplifies to 1, and its derivative with respect to x is 0.

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