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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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A solenoidal coil has 50 turns per cm\mathrm{cm} along its length and a cross-sectional area of 4×10−4 m2.2004 \times 10^{-4} \mathrm{~m}^2 .200 turns of another wire is wound round the first solenoid co-axially. Both the two coils are electrically insulated from each other. Calculate the mutual inductance between the two coils.
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Correct option: B
5.03×10−4H5.03 \times 10^{-4} \mathrm{H}
Option B (5.03×10−4H5.03 \times 10^{-4} \mathrm{H}) is correct because the mutual inductance is calculated using the formula involving the number of turns and area.

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