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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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If x>13x > \frac{1}{{\sqrt 3 }}, then x>13x > \frac{1}{{\sqrt 3 }} equals
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Correct option: B
−π+3tan⁡−1x- \pi + 3{\tan ^{ - 1}}x
Option B (−π+3tan⁡−1x- \pi + 3{\tan ^{ - 1}}x) is correct because it represents the correct simplification of the given expression when x>13x > \frac{1}{{\sqrt 3 }}.

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