JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Understanding +4 | -1

Using Boolean algebra, the value of

(A \cdot B)+A

is equal to

View answer and explanation

Correct option: D

(A \cdot \bar{A})+A

Option D (

(A \cdot \bar{A})+A

) is correct because using Boolean algebra,

(A \cdot B)+A

simplifies to A, which is equivalent to

(A \cdot \bar{A})+A

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