JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

\cos ^{-1}\left(\frac{2}{3 x}\right)+\cos ^{-1}\left(\frac{3}{4 x}\right)=\frac{\pi}{2}\left(x>\frac{3}{4}\right)

, then

x

is equal to:

View answer and explanation

Correct option: D

\frac{\sqrt{145}}{12}

Option D (

\frac{\sqrt{{145}}}{{12}}

) is correct because solving the given equation using trigonometric identities leads to

x = \frac{\sqrt{{145}}}{{12}}

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\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1

x

{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)