If ${\sin ^{ - 1}}\left( {\frac{x}{5}} \right) + {\rm{cose}}{{\rm{c}}^{ - 1}}\left( {\frac{5}{4}} \right) = \frac{\pi }{2}$, then value of $x$ is

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

{\sin ^{ - 1}}\left( {\frac{x}{5}} \right) + \mathrm{cose}{\mathrm{c}^{ - 1}}\left( {\frac{5}{4}} \right) = \frac{\pi }{2}

, then value of

x

View answer and explanation

Correct option: B

Option B (3) is correct because by using the property that

{\sin ^{ - 1}}x + {\csc ^{ - 1}}y = \frac{\pi }{2}

implies

x = \frac{1}{y}

, we can solve for x.

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