The solution set of ${x^2} + x + \left| x \right| + 1 < 0,$ is

$\left( { - \infty ,0} \right)$

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

The solution set of

{x^2} + x + \left| x \right| + 1 < 0,

View answer and explanation

Correct option: D

\phi

Option D (

\phi

) is correct because the inequality

{x^2} + x + |x| + 1 < 0

has no real solutions for any value of x.

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