JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

for

0 < x < 2,\frac{d}{{dx}}\left( {{{\tan }^{ - 1}}\sqrt {\frac{{1 + \cos \frac{x}{2}}}{{1 - \cos \frac{x}{2}}}} } \right)

is equal to

View answer and explanation

Correct option: A

\frac{{ - 1}}{4}

Option A (

\frac{{ - 1}}{4}

) is correct because after simplifying the expression inside the arctangent function, the derivative is a constant.

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