JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

y = \sqrt {x + \sqrt {y + \sqrt {x + \sqrt {y + \ldots \infty } } } }

, then

\frac{{dy}}{{dx}}

is equal to

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the calculated derivative

\frac{{dy}}{{dx}} = \frac{{{{y^2} - x}}}{{{{y^3} - xy - 1}}}

does not match any of the given options.

More Questions from DIFFERENTIATION

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x

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y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^{3}\right)

z = y + f\left( v \right),

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v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}